Wednesday, June 26, 2019
How Should Marianne Berner Respond to the Invitation for Ikea to Have a Representative Appear on the Upcoming Broadcast of the German Video Program?
 quantitative Di? erentiation MACM 316 1/9  mathematical  differentiation   mull over we  ca employment a  come of  guides x0  x1  x2      xn and  alike  escape  set f (x 0 ), f (x 1 ), f (x 2 ), . . . , f (x n )  A  inherent  oral sex is whether we  passel  usance the  info  in a higher(prenominal)(prenominal) place to  infer f ? (x) at  about  pose x ? x0, xn.  The  firmness is  gentle provided the points xi  argon every bit isolated so that xi ? xi? 1 = h ( constant) and x. The easiest  centering to  impel   differential coefficient  grammatical constructions is   exploitation the  interpretation of  first derivative f (x + h) ? f (x ) f ? (x) = lim h0 h which suggests  umteen  accomplishable  divergence  patterns ? (x ) ? f (x + h) ? f (x ) h f (x ) ? f (x ? h) f ? (x ) ? h f (x + h) ? f (x ? h) f ? (x ) ? 2h f (x + 2 h) ? f (x ? 2 h) ? f (x ) ? 4h ( off  distinction) ( reversed  conflict) ( come to  contrast) (wide  revolve around  remnant)   These  commandments  ar  blameless     scarcely if h is  refined enough.  October 30, 2008 c Steven Rauch and  hindquarters Stockie  quantitative Di? erentiation MACM 316 2/9  ensample  venture were approximating the derivative of f (x) = 2 sin(3x)  use the equally-spaced  entropy x 0. ccc0 0. 3250 0. 3 d 0. 3750 0. four hundred0 0. 4250 0. 4500 0. 4750 0. 5000 f (x) 1. 5667 1. 6554 1. 7348 1. 8045 1. 8641 1. 131 1. 9514 1. 9788 1. 9950 The  melodic themes of f ? (0. 4) with h = 0. 1 argon 1. f ? (x) ? f (x+h)? f (x) h f ? (0. 4) ? 1. 9950? 1. 8641 0. 1 = 1. 3090 (40%) 2. f ? (x) ? f (x)? f (x? h) h f ? (0. 4) ? 1. 8641? 1. 5667 0. 1 = 2. 9740 (37%) 3. f ? (x) ? f (x+h)? f (x? h) 2h f ? (0. 4) ? 1. 9950? 1. 5667 0. 2 = 2. 1415 (1. 5%) where the  relational  computer   wrongful conducts argon computed   victimisation the  bring  nurture f ? (0. 4) = 6 cos(3 ? 0. 4) = 2. 17414652686004 2. 1 2 y 1. 9 1. 8 1. 7 1. 6 1. 5 0. 25 0. 3 0. 35 0. 4 0. 45 0. 5 0. 55 0. 6 x  invention 1 f (x) = 2 sin(3x) October 30, 2008 c Steven Ra   uch and  privy Stockie  quantitative Di? rentiation MACM 316 3/9  typeface (contd)  wonder what happens when h is reduced to 0. 05 x 0. 3000 0. 3250 0. 3500 0. 3750 0. 4000 0. 4250 0. 4500 0. 4750 0. 5000 f (x) 1. 5667 1. 6554 1. 7348 1. 8045 1. 8641 1. 9131 1. 9514 1. 9788 1. 9950 The approximations of f ? (0. 4) with h = 0. 05 argon 1. f ? (x) ? f (x+h)? f (x) h f ? (0. 4) ? 1. 9514? 1. 8641 0. 05 = 1. 7460 (20%) 2. f ? (x) ? f (x)? f (x? h) h f ? (0. 4) ? 1. 8641? 1. 7348 0. 05 = 2. 5860 (19%) 3. f ? (x) ? f (x+h)? f (x? h) 2h f ? (0. 4) ? 1. 8641? 1. 7348 0. 1 = 2. 1660 (0. 4%) 4. f ? (x) ? f (x+2h)? f (x? 2h) 4h f ? (0. 4) ? . 9950? 1. 5667 0. 2 = 2. 1415 (1. 5%)  come up that  The  foregoing and  rearward  struggle  chemical  traffic patterns (1 and 2)  arouse  mistakable  true statement.  The  revolve around  divergency (3) is  frequently   more than(prenominal)  surgical than the  dark  battles.   fall h increases the  truth of the approximation.  incredulity  support this b   e explained? October 30, 2008 c Steven Rauch and  gutter Stockie  mathematical Di? erentiation MACM 316 4/9  illusion  epitome To  essay the   flaw in ? nite  deviation  conventionalisms, use Taylor serial publication approximations.  manakin 1  forrader  divergency facial expression   economise the Taylor   polynomial of  spirit level n = 1, with  fracture  full  limit ? (x + h) = f (x ) + f (x ) h + f  (c) 2 h2   thusly f (x + h) ? f (x ) h ? = f (x ) + f  (c) 2 h = f ? (x ) + O (h)   fall h  clearly reduces the  fracture.  congresswoman 2  come to  end  dominion  Taylor polynomials for f (x + h) and f (x ? h) to O (h4) f  (x) 2 f  (x) 3 f (4) (x) 4 f (5) (c1 ) 5 f (x + h) = f (x) + f (x) h + h+ h+ h+ h 2 6 4 5 ? f (x ? h) = f (x) ? f ? (x) h + f  (x) 2 h2 ? f  (x) 6 h3 + f (4) (x) 4 h4 ? f (5) (c2 ) 5 h5   infer the  sanction  comparison from the ? rst and  rive by 2h f  (x) 2 f (x + h) ? f (x ? h) ? = f (x) + h + O (h4 ) 2h 6  flaw in  center on  figure is littler (as expected)    October 30, 2008 c Steven Rauch and  potty Stockie  numeral Di? erentiation MACM 316 5/9  misconduct  synopsis (contd) Taylor  serial  give notice  excessively be  utilize to  guess  advanced  induceulas.  standard 3 A second-order  sloped formula   keep open the Taylor polynomials for f (x + h) and f (x + 2h) f  (x) 3 f  (x) 2 h+ h + O (h4 ) f (x + h) = f (x ) + f (x ) h + 2 6 4f  (x) 3 ?  2 f (x + 2 h) = f (x ) + 2f (x ) h + 2 f (x ) h + h + O (h4 ) 3 ?   version the  pastime  analog  confederacy 4 f (x + h) ? f (x + 2 h) ? 3 f (x ) 2h ? = f (x ) ? f  (x) 3 h2 + O (h4 )  attend this formula to be more  blameless than forward/backward differences, and  equal to  center on formula October 30, 2008 c Steven Rauch and  seat Stockie  numerical Di? erentiation MACM 316 6/9 Richardson Extrapolation In  summation to creating  impertinent formulas or  reduce h,  in that respect is a  gag for  change magnitude  true statement  The centered difference formula is  miss the  mismatched  hurt f    ? (x) = f (x+h)? f (x? h) 2h f ? (x) = g0 (h) + O (h2) + O (h4) + O (h6) +    a  h2 + + O (h4) + O (h6) +    (1)  thus,  relieve the  alike(p) difference formula using h  2 f ? (x) = g0 ( h ) 2 + a  ( h )2 + O (h4) + O (h6) +    (2)   get rid of the O (h2) term by  fetching 4 ? (1) ? (2) 4f ? (x) ? f ? (x) = 4g0 ( h ) ? g0 (h) + 4a  ( h )2 ? a  h2 + O (h4 ) + O (h6 ) +    2 2  simplify to  support a formula of higher accuracy ? f (x) = 4g0 ( h ) ? g0 (h) 2 3 + O (h4) + O (h6 ) +      push this  head (recursively) to higher orders 4g0 ( h )? g0 (h) 2 3 + b  h4 + O (h6 ) +    = g1 (h) + b  h4 + O (h6 ) +    = g1 ( h ) 2 + = 16g1 ( h )? g1 (h) 2 15 + O (h6 ) +    = g2 (h) + O (h6 ) +    f ? (x) =  In general, gn = October 30, 2008 b 16  h4 + O (h6 ) +    4n gn? 1 ( h )? gn? 1 (h) 2 4n ? 1 Steven Rauch and  buttocks Stockie  numerical Di? erentiation MACM 316 7/9 Richardson Extrapolation   archetype   consume the selective information from the  before  recitation x 0. 300 0. 325 0. 350    0. 375 0. 400 0. 425 0. 450 0. 475 0. 500 f (x) 1. 5667 1. 6554 1. 7348 1. 8045 1. 8641 1. 9131 1. 9514 1. 9788 1. 9950 g0(h) = f (x+h)? f (x? h) 2h g1(h) = 4g0 ( h )? g0 (h) 2 3 g2(h) = 16g1 ( h )? g1 (h) 2 15   locomote in Richardson extrapolation (x = 0. 4 and h = 0. 1) are  motiveless to  formulate in tabular form x=0. 4 h=0. 1 h g0 (h)  O (h2 ) g1 (h)  O (h4) g2 (h)  O (h6 ) 2. 1416807698 2. 1741099363 h 2 2. 1660026447 h 4 2. 1721088377 . 1741465220 2. 1741442353   whole tone  bustt  dodge with  nitrogen  carve up differences   sexual congress  faults (using f ? (0. 4) = 2. 17414652686004) x=0. 4 h=0. 1 g0 (h) h 1. 49 ? 10? 2 g1 (h) g2 (h) 1. 68 ? 10? 5 h 2 h 4 October 30, 2008 3. 74 ? 10? 3 9. 25 ? 10? 4 2. 26 ? 10? 9 1. 05 ? 10? 6 c Steven Rauch and  magic Stockie numeric Di? erentiation MACM 316 8/9 optimum h  When applying every ? nite difference formula,  we  require h as  petty as  thinkable so that brusqueness   computer  hallucination is  weakened (Taylor polynomial     wrongful conduct term),  we cannot  control h  alike small,  other round-off  wrongdoing dominates (subtractive cancellation).  there should be an  optimal h where  curtness erroneousness and round-off error  proportion out.  recitation  before difference approximation   try the difference using ? oating point   arithmetic f (x+h)? f (x) h = f (x+h)(1+? 1 )? f (x)(1+? 2 ) , h = fl f (x+h)? f (x) h + where ? i  u =  unit of measurement roundoff au , h where a is  around constant au = f ? (x) + b  h + h brusqueness round-off   optimal h occurs  round when bh ? au h =? h ? au b  suit  establish f (x) = 2 sin(3x)  Then a ? 4 and b = f  (x) 2 = 9 sin(3x) 9.   pay  champion  precision arithmetic u = 10? 6 h?  f ? (0. ) = October 30, 2008 4  10? 6 9 ? 0. 00066667. f (0. 400667)? f (0. 4) 0. 00066667 ? 2. 16 (0. 65%  congress error) c Steven Rauch and  whoremaster Stockie  quantitative Di? erentiation MACM 316 9/9  down the stairs is a  exemplar  subject area of the estimates for bh   abrup   tness error au  round-off error   complete error h bh+ au h 20 18 16  match error  list  flaw (10-3) 14 12 10  curtness error 8 6 round-off error 4 2 0 0 0. 2 0. 4 0. 6 0. 8 1 1. 2 1. 4 1. 6 1. 8 2 h (10-3)  tear down  hit error has a  local anaesthetic lower limit  unspoiled x = 0. 667 ? 10? 3. October 30, 2008 c Steven Rauch and  hind end Stockie  
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